5x^2-19x+35=0

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Solution for 5x^2-19x+35=0 equation:


Simplifying
5x2 + -19x + 35 = 0

Reorder the terms:
35 + -19x + 5x2 = 0

Solving
35 + -19x + 5x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
5 the coefficient of the squared term: 

Divide each side by '5'.
7 + -3.8x + x2 = 0

Move the constant term to the right:

Add '-7' to each side of the equation.
7 + -3.8x + -7 + x2 = 0 + -7

Reorder the terms:
7 + -7 + -3.8x + x2 = 0 + -7

Combine like terms: 7 + -7 = 0
0 + -3.8x + x2 = 0 + -7
-3.8x + x2 = 0 + -7

Combine like terms: 0 + -7 = -7
-3.8x + x2 = -7

The x term is -3.8x.  Take half its coefficient (-1.9).
Square it (3.61) and add it to both sides.

Add '3.61' to each side of the equation.
-3.8x + 3.61 + x2 = -7 + 3.61

Reorder the terms:
3.61 + -3.8x + x2 = -7 + 3.61

Combine like terms: -7 + 3.61 = -3.39
3.61 + -3.8x + x2 = -3.39

Factor a perfect square on the left side:
(x + -1.9)(x + -1.9) = -3.39

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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